b^2+20b-96=0

Solution for b^2+20b-96=0 equation:

Simplifying
b2 + 20b + -96 = 0

Reorder the terms:
-96 + 20b + b2 = 0

Solving
-96 + 20b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-24 + -1b)(4 + -1b) = 0

Subproblem 1
Set the factor '(-24 + -1b)' equal to zero and attempt to solve:

Simplifying
-24 + -1b = 0

Solving
-24 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '24' to each side of the equation.
-24 + 24 + -1b = 0 + 24

Combine like terms: -24 + 24 = 0
0 + -1b = 0 + 24
-1b = 0 + 24

Combine like terms: 0 + 24 = 24
-1b = 24

Divide each side by '-1'.
b = -24

Simplifying
b = -24
Subproblem 2
Set the factor '(4 + -1b)' equal to zero and attempt to solve:

Simplifying
4 + -1b = 0

Solving
4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = 0 + -4
-1b = 0 + -4

Combine like terms: 0 + -4 = -4
-1b = -4

Divide each side by '-1'.
b = 4

Simplifying
b = 4
Solution
b = {-24, 4}